Grepping text by providing line numbers.

Shell Programming and Scripting
1

Dear Friends,
I have a flat file from which I want to grep line no. 7,10, 19 to 35, 37.
How can it be done?

Thank you in advance
Anushree

2

Hi.

When you say "grep lines", do you mean extract lines?

There are a number of tools that can do this.

But based on what you asked, this should work...

sed "7p;10p;19,35p;37p;d" my_file | grep "....."

3 
awk 'NR ~ /^(7|10|19)$/' file
4

Use gawk, nawk or /usr/xpg4/bin/awk on Solaris:

awk 'NR~/^7|1[09]|2[0-9]|3[0-5,7]$/' infile
5

One way to do it in perl:

perl -ne 'BEGIN{foreach $i (7,10,(19..35),37){$x{$i}=1}}{print if $x{$.}==1}' infile

tyler_durden

6

I have to read more carefully,
I corrected my post.

Using the same logic with Perl:

perl -ne'$.=~/^7|1[09]|2[0-9]|3[0-5,7]$/and print' infile
7

Hey friends
Almost all solutions worked fine
Thank you for the quick reply.
Take care.