Greping certain lines

One of my outout is like this as shown below. How can I grep only the lines after the line "Affected files ...". No of lines after the line "Affected files ..." may vary.

$ cat file_A

Change 149133 by csaha@test_depo_csaha on 2006/02/08 01:40:57 *pending*

    This is to test change \#

Affected files ...

... //depot/users/csaha/chirantan/R&D1.doc#1 edit
... //depot/users/csaha/my-scripts/ecmsbuild.sh#2 edit
... //depot/users/csaha/my-scripts/eta noster gora.txt#1 add
... //depot/users/csaha/my-scripts/fs-dtls.sh#2 edit
... //depot/users/csaha/my-scripts/fs_usage_monitor.sh#2 edit
... //depot/users/csaha/my-scripts/server_info.sh#2 edit

You could do this.

sed -n -e '/Affected files/,$p' | grep needle

It will gather all lines from "Affected files" till end of file.

Thanks for the code dude

Only this was enough

$ cat file_A | sed -n -e '/Affected files/,$p' 
Affected files ...
 
... //depot/users/csaha/chirantan/R&D1.doc#1 edit
... //depot/users/csaha/my-scripts/ecmsbuild.sh#2 edit
... //depot/users/csaha/my-scripts/eta noster gora.txt#1 add
... //depot/users/csaha/my-scripts/fs-dtls.sh#2 edit
... //depot/users/csaha/my-scripts/fs_usage_monitor.sh#2 edit
... //depot/users/csaha/my-scripts/server_info.sh#2 edit

cat file_A | sed -n -e '/Affected files/,$p'

That is a UUOC

sed -n -e '/Affected files/,$p' file_A 

UUOC means ?

See this - UUOC