Grep strings from file and put in Column

Dear Experts,

My file contains below-

GET:SUB:ISI,432350414557432;
RESP:0:MD,019352020633:ISI,432350414557432:T11,1:T21,1:T22,1:B16,1:T62,1:BAIC,0:BAOC,1:BOIC,0:BIRO,0:BORO,0:PAID,1;
GET:SUB:ISI,432350414581060;
RESP:0:MD,019352020743:ISI,432350414581060:T11,1:T21,1:T22,1:B16,1:T62,1:BAIC,0:BAOC,0:BOIC,0:BIRO,0:BORO,0:PAID,0;
GET:SUB:ISI,432350211029016;
RESP:11000003;
GET:SUB:ISI,432350414073552;
RESP:0:MD,019352032067:ISI,432350414073552:T11,1:T21,1:T22,1:B16,1:T62,1:BAIC,0:BAOC,0:BOIC,0:BIRO,0:BORO,0:PAID,1;

I want make a script like below-

if find-
RESP:0:MD,019352020633:ISI,432350414557432:T11,1:T21,1:T22,1:B16,1:T62,1:BAIC,0:BAOC,1:BOIC,0:BIRO,0:BORO,0:PAID,1;
then PAID,1 printf "paid"
else PAID,0 printf "non-paid"

if find-
RESP:11000003
then RESP:11000003 printf "not-exist"

So, after run the script output will be for the above file-

paid
non-paid
not exits
paid

//purple

cat file | awk '/PAID,1/ { print "paid";} /PAID,0/ {print "non-paid";} /RESP:11000003/ {print "not exists"}'

great man Its working. And many thanks for your prompt response

//purple