Grep string in files and list file names that contain the string

Shell Programming and Scripting
1

Hi,
I have a list of zipped files. I want to grep for a string in all files and get a list of file names that contain the string. But without unzipping them before that, more like using something like gzcat.
My OS is:
SunOS test 5.10 Generic_142900-13 sun4u sparc SUNW,SPARC-Enterprise

2

Do your system has zgrep ??

3

no, don't have zgrep.

4

Without that you could use

zcat (in case of .Z files)

5

Hmmm, not really sure how to use that?

6

Kind of the same way you'd use cat...

If you don't have gzcat it's simple enough to make one:

for FILE in *.gz ; do gunzip < $FILE ; done | ...
7

gzcat is OK

gzcat *.gz|grep string

But that do not give me the file names in which the string is found.
I also tried:

gzcat *.gz|grep -l string

But that doesn't work, it gives me an error.
So my question is, is there any way to get the file names using gzcat?

Thanks!

8

You can either gzcat *.gz to a temp directory, and run grep -l on that, or you need a for loop like

for FN in *.gz; do gzcat "$FN" | grep string && echo "$FN"; done
1 Like
9

It works!

Thanks to all!!