grep string containing [] brackets

UNIX for Advanced & Expert Users
1

Hello,

I am trying to grep string with square brackets.

for example I want to grep the below string in log.txt file.

 
This is a test[1]

thanks in advance.

2 
  find . -name "*" | xargs grep '\[*\]' *

Use this command

---------- Post updated at 11:15 AM ---------- Previous update was at 11:14 AM ----------

or simply u can use in current directory

 grep '\[*\]' *

Or from root u have to find use / instead of .

  find / -name "*" | xargs grep '\[*\]' *
3

imho you just have to escape the leading square bracket;

$ grep "test\[1]" log.txt

good luck, and success !

alexandre botao
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