Grep showing all files name of the directory

Shell Programming and Scripting
1

Hi All,

Can any one help me here.I'm getting whole files name of the directory along with the grep result.

below is the code

 
var=`grep -i '127.3.3.1' _record`
echo $var
2

What is "whole files name"?
Is your grep aliased?

3

Thanks for reply Rudic !!

Whole files name here means all the other files name which is present in the current directory.

For you refrence o/p of the above code.

 
"26731","47710","TEST","ADMIN","127.3.3.1","select 1 1.cron_dup 1.out 1.sql 912650.pln abc.out aginity A.out B.out check234 C.out create_mytable create_mytable.out dynamictables1 empty et1_region_flat_file exclusionfield1 exclusionfield1.out exclusionfilterchar file1 final_report.out fstm greatest.cpp greatest.o_spu10 greatest.o_x86 health.sh health_test.sh hostbackup if_test load1.dat long long_aginity longrunning.csv longrunning_edit.csv longrunning_edit.csv_old msg1.out msgatach.out msgattach.out msgBody.txt msg.out MSTR mytest_2370271.pln my_test_table_in_place2370368.pln Netezza permission query_5674337_final query_test rav_a.out _record region row.out runaway runaway_1 runaway_3 runaway_3_msg.out runaway_new.sh runaway.out runaway_priya.sh runaway_test sample.out session size_info_old.out size_info.out size.out sql_not_in_place_of_view.out sql_not_in_place_of_view.out1 sql_table_in_place_of_view.out sql.txt sql.txt2 sqltxt26 sqltxt26.out sql.txt2_format sql.txt2.out stats sts.log sytm.out sytm.txt TABLE1.1 temp1 temp1.csv temp1.out temp2.out temp3.out test000 test007 test101 test101.csv test102 test103 test104 test105 test1.sh test222 test2222 test222_msg.out test22.sh test23.sh test333 test333.out test444 test_aatch test_case test_create test_create.create_out test_create.create.out test_diag test_grep_ip testkkk testkkk.out test_session
4

Well, I guess that's the line in _record that has 127.3.3.1 in it.

5

No Rudic.

These are the files name in current directory.Only till select is the content in the file '_record'

6

Is _record a flat file, or a directory?

Is that your entire script, or is there some other stuff around it?

7

_record is a flat file

This is the only thing in the script.

 
var=`grep -i '127.3.3.1' _record`
echo $var
8

I assume you've checked that _record doesn't actually have a bunch of filenames in it? What does the relevant line look like in the file?

9

hi try
can you try

cat _record| grep -i <your pattern>

instead of

grep -i <pattern> <filename>

ideally they both should be producing the same result.

10

I presume your file "_record" contains some DB-statement, maybe something like "select * from ...". Your problem is a simple case of neglecting proper quoting in the shell. Try the following:

echo "*"
echo *

and you will notice that the first produces a single asterisk while the second one produces a list of all files, quite similar to the output of "ls". The reason is, that the shell evaluates some expressions - the asterisk being among them - itself, instead of passing it to the program. Issue a

ls -l *

and the following will happen: first "*" is being expanded to a list of all file names, then "ls" is given this list and displays the files one by one. The same has happened here: by

echo $var

you basically have executed a

echo ... select * from ...

and the asterisk is duly expanded. As you should NOT USE BACKTICKS UNDER ANY CIRCUMSTANCE (really!) you should modify your code this way:

var=$(grep -i '127.3.3.1' _record)
echo "$var"

I hope this helps.

bakunin