grep command

Shell Programming and Scripting
1

Hi
I am looking for a way to grep a range of data within a file.
for example, I need to grep any row that has a number between 999 to 10000.

Does anyone know how to do it?

Thanks in advance!

2

Personally, I'd tackle this with sed and the shell....

Let's assume your input file contains only one numeric value on each line, which may or may not contain text too, e.g.

$ cat > input_file
1
100
500
998
999
1000
2000
there is 4500 on this line
5000
9999
10000
10001
99999

Then, a script such as the following would give you the results you want...

$ cat > extract_it.sh
#!/bin/sh

while read line; do
  value=`echo ${line} | sed 's/^[^0-9]*\([0-9]\{3,5\}\)[^0-9]*$/\1/'`
  if [ "${value}" -ge "999" -a "${value}" -le "10000" ]; then
     echo "${line}"
  fi
done < ./input_file

Cheers
ZB