Grep command showing wrong output in Linux

Shell Programming and Scripting
1

Hi All
I am trying to run a script in linux wherein i have a command like this

grep ^prmAttunityUser= djpHewr2XFMAttunitySetup_ae1_tmp
djpHewr2XFMAttunitySetup_ae1_tmp is a temporary file in which the user value is stored but this command in the script returns me balnk value whereas it has a value.

Not understanding why is this command in the scipt returning a blank value. Can anyone please help me on this.

Thanks

2

Are you sure that you have a line that starts with prmAttunityUser in the file djpHewr2XFMAttunitySetup_ae1_tmp

because testing here, that format works perfectly

3

The value does exists in the file.$prmAttunityUser=ais

4

$prmAttunityUser=ais =/= prmAttunityUser=ais did you mean to grep for
grep ^\\\$prmAttunityUser= djpHewr2XFMAttunitySetup_ae1_tmp

5

The entire logic is this

for y in $params; do
       for pf in $parfile; do
          ret=`grep \^$y\= $pf`
          if [ "$ret" != "" ]; then
             prm=$ret
          fi
       done
       if [ "$prm" == "" ]; then
          echo "parameter not found ($y) for job ($x.$invocation_id)"
          echo "Returning value 1"
          return 1
          exit
       else
          prmString[$cnt]="${prmString[$cnt]}  -param $prm"
       fi
    done

HEre parfile contains a value like prmAttunityuser = ais but still it returns blank.