Grep all the columns based on a particular column

UNIX for Advanced & Expert Users
1

This is the data file that I have

21879, 0, 22, 58, 388
0, -1, 300, 1219172589765, 1708, 0, 200, 21891, 0, 0, 33, 309
0, -1, 300, 1219172591478, 1768, 0, 200, 22505, 0, 0, 33, 339
0, -1, 300, 1219172593251, 1738, 0, 200, 21888, 0, 1, 33, 308
0, -1, 300, 1219172594995, 633, 0, 200, 24878, 0, 0, 33, 272
0, -1, 300, 1219172595631, 568, 0, 200, 22371, 0, 0, 34, 269
0, -1, 300, 1219172596204, 569, 0, 200, 26014, 0, 2, 35, 272
0, -1, 300, 1219172596777, 517, 0, 200, 22377, 0, 0, 33, 287

I need to grep all the columns based on the third column value from the left. For example in this case I want all the columns and the rows based on the value of '300'

Could someone tell me how this can be done

Thanks
Poornima

2

What does "all the columns and the rows based on the value of '300'" mean?

awk -F , '$3 == 300' file

... perhaps?

3

awk -F "," '($3 == 300) {print $0}' filename