Getting value of a pattern preceding another pattern

Shell Programming and Scripting
1

I have a file like this
-------------------------------

[2012-11-12 :  11:59
 some text
 some moe text
  ERR-XXXXX
soe more text
]
[2012-11-12 : 12:00 blala blah blah]
[2012-11-12 :  12:01
 some text
 some moe text
  ERR-XXXXX
soe more text
]
[2012-11-12: 12:02  some other text ]

--------------------------------------

I need a way to find the timestamp preceding the ERR-XXXXX

Here XXXX deonoes any any numeric string 00000-99999
that is a output like this

2012-11-12 :  11:59-ERR-XXXXX
2012-11-12 :  12:01-ERR-XXXXX
2 
awk '/\[2012/{a=$0}/^ERR/{print a"-"$0}' input.txt
[2012-11-12 : 11:59-ERR-XXXXX
[2012-11-12 : 12:01-ERR-XXXXX

---------- Post updated at 10:01 AM ---------- Previous update was at 09:59 AM ----------

awk '/\[2012/{sub("\\[","",$0);a=$0}/^ERR/{print a"-"$0}' input.txt
2012-11-12 : 11:59-ERR-XXXXX
2012-11-12 : 12:01-ERR-XXXXX
1 Like
3

the command is working in the shell.
However when calling this same command from a function
$0 is getting replaced by KSH and the date part is not coming only ERR part is coming

like this

-ERR-XXXXX some more text
-ERR-XXXXX some other text
4

can you show your function and how you are calling the function?

5 
myFunc(){
echo "In Function ...processing $1"

echo "awk '/\[$1/{sub("\\[","",$0);a=$0}/^ORA/{print a"-"$0}'" 
awk '/\[$1/{sub("\\[","",$0);a=$0}/^ERR/{print a"-"$0}' $2.log>>$3 

awk '/\[$1/{sub("\\[","",$0);a=$0}/^ERR/{print a"-"$0}' $2_$4>>$3 

awk '/\[$1/{sub("\\[",""$0);a=$0}/^ERR/{print a"-"$0}' $2_$5>>$3 
 
}

Calling

myFunc "$currentMonth\/$currentDay\/$currentYearYY" SystemOut $inputFile "$currentYearYY.$currentMonth0.$currentDay0*"  $prevDayYr.$prevDayMonth.$prevDayDay