Getting part of a filename

Shell Programming and Scripting
1

Hi All,
I'm trying to get part of a filename and my skill with regular expression are lacking. I know I need to use SED but have no idea how to use it. I'm hoping that someone can help me out. The file names would be:

prefix<partwewant>suffix.extension
the prefix and suffix are always 3 characters and always the same [ABC, XYZ]. eg.

ABCN204867362XYZ.jpg
ABCC2039458XYZ.jpg
ABC2049583XYZ.jpg

Any ideas on how I can extract the middle part of the name?

Thanks in advance

2 
 
$ sed -e 's/.*ABC//' -e 's/XYZ.*//' test
N204867362
C2039458
2049583

$ cat test
ABCN204867362XYZ.jpg
ABCC2039458XYZ.jpg
ABC2049583XYZ.jpg
1 Like
3

Thanks heaps itkamaraj.
Based on your command, how can I add back the file extension?

4

Using standard parameter expansion:

for f in ABC*XYZ.*; do
  _t=${f#???} _e=${_t#${_t%%???.*}}
  printf 'middle:\t%s\n' "${_t%$_e}"
  printf 'ext:\t%s\n' "${_e#???}"
done

Example output:

% ls -l
total 0
-rw-r--r-- 1 sysadmin None 0 Jul 22 11:41 ABC2049583XYZ.jpg
-rw-r--r-- 1 sysadmin None 0 Jul 22 11:42 ABCC2039458XYZ.png
-rw-r--r-- 1 sysadmin None 0 Jul 22 11:41 ABCN204867362XYZ.jpg
% for f in ABC*XYZ.*; do
  _t=${f#???} _e=${_t#${_t%%???.*}}
  printf 'middle:\t%s\n' "${_t%$_e}"
  printf 'ext:\t%s\n' "${_e#???}"
done  
middle: 2049583
ext:    .jpg
middle: C2039458
ext:    .png
middle: N204867362
ext:    .jpg
5 
$ sed -e 's/.*ABC//' -e 's/XYZ.*/.jpg/' test