Get up one directory of location as variable

Linux and Unix-Like Red Hat
1

May i know how can i pass up one of a location to a variable in script file with command in stead of hardcode?

saying in my script file:

maindir = "/opt/xSystem/config"
upOneDir = ?????
echo $upOneDir

I have to use command to pass "/opt/xSystem"
to variable upOneDir.

Please advise..

many thanks!

2 
echo $mainder |awk -F/ '{gsub($NF,"");print}' |sed 's/.$//'
1 Like
3

hello Ningy,

thanks for your prompt reply.

I have tested your advice but still unable to get the thing work.

Please advice again.
Thank you

---------- Post updated at 04:34 AM ---------- Previous update was at 03:39 AM ----------

and why below only works for pwd.. but not other location..

dir1=$PWD
echo $dir1

higher_dir=$(cd ..
pwd)
echo higher_dir

this doesn't work when i replace the $PWD with "/opt/xSystem"

please advice..

Many thanks!

4

what output did u get when u ran my command above coz it worked for me..

5

What shell do you use? In case of bash there are some nice string manipulation features:

maindir=/opt/xSystem/config
upOneDir=${maindir%/*}
echo $upOneDir
/opt/xSystem
1 Like
6

hello ningy..

it shows the blank.. hmm i did edit "maindir" from your code

thanks yea

---------- Post updated at 12:22 PM ---------- Previous update was at 12:21 PM ----------

hi cero,
thanks! it is working.