Get free space of file system

Shell Programming and Scripting
1

Hi guys,

I'm trying to get free space in GB of file system into parameter.
I have the following code:

> cat get_free_space_FS.ksh
#! /bin/ksh

FS=/dw/mar
FreeSpace=`df -h | grep $FS | awk '{print $4}'`
echo $FreeSpace

> ./get_free_space_FS.ksh
362G

My question is ,how can I cut in the "df -h" command the "G" sign from the output , because I want to do manipulations on a numeric result?

Thanks in advance,
Nir

2

Hi.

Try changing this:

FreeSpace=`df -h | grep $FS | awk '{print $4}'`

To this:

FreeSpace=`df -h | grep $FS | awk '{print $4 + 0}'`
3

one way, using similar to what you have, and different FS for purposes of example:

#  df -h /tmp
Filesystem             size   used  avail capacity  Mounted on
swap                    78G   670M    77G     1%    /tmp

so,


#  df -h /tmp |awk 'NR==2{print substr($4,1,length($4)-1)}'
77

using grep has potential to hit multiple matches, so df the FS directly...

HTH

---------- Post updated at 11:11 AM ---------- Previous update was at 11:08 AM ----------

This is nice.... caveat - works for nawk, but not (solaris) awk

4 
df -k | grep $FS | awk '{printf "%d\n",$4/1024/1024}'

Remove a division if you need MiB instead of GiB.

And if you need the free space of a certain mount point you can even shorten it to

df -k $FS | awk '{printf "%d\n",$4/1024/1024}'
5

Hi pludi/Tytalus,

Thanks a lot!
very nice solutions.

Best regards,
Nir