get file names from the list

Shell Programming and Scripting
1

Hi Experts,
Here is my scenario:
Am maintaining a file which has list of logs with complete path and file names like bleow

a/b/c/Daily/file1_20111012.log
d/e/f/Monthly/file1_20111001.log
g/h/Daily/file1_20110120.log
i/Daily/file1_20110220.log

How to copy the file names frm the list using script?

Month will be passed as runtime argument

two scenarios:
1) if the dir is Monthly than I have to get specfic month log (d/e/f/Monthly/file1_20111001.log) frm the list

2) if the dir is Daily than I have to get specfic month all logs (a/b/c/Daily/file1_20111001.log to a/b/c/Daily/file30_20111030.log) frm the list

If somebody can help me here would be highly appreciated!!!

2 
$ cat test.sh
#! /bin/bash

while read x
do
    echo $x | grep -q "Daily"
    if [ $? -eq 0 ]
    then
        [ `echo $x | cut -d_ -f2 | cut -c5-6` -eq $1 ] && echo $x
        continue
    fi
    echo $x | grep -q "Monthly"
    if [ $? -eq 0 ]
    then
        [ `echo $x | cut -d_ -f2 | cut -c5-6` -eq $1 ] && echo $x
    fi
done < inputfile
$
$ ./test.sh 10
a/b/c/Daily/file1_20111012.log
d/e/f/Monthly/file1_20111001.log
$
3

balajesuri,

Thanks for quick reply, whn I executed got below error

grep: illegal option -- q
Usage: grep -hblcnsviw pattern file . . .
4

Your version of grep doesn't support -q switch.
Try this:

echo $x | grep "Daily" >> /dev/null
5

balajesuri,

modified script as below

#! /bin/bash
while read x
do
    echo $x | grep "DAILY"  >>/dev/null
    if [ $? -eq 0 ]
    then
        [ `echo $x | cut -d_ -f2 | cut -c5-6` -eq $1 ] && echo $x
        continue
    fi
    echo $x | grep "MONTHLY"  >>/dev/null
    if [ $? -eq 0 ]
    then
        [ `echo $x | cut -d_ -f2 | cut -c5-6` -eq $1 ] && echo $x
    fi
done < /home/list.txt

whn executed got below error

./tst.sh: line 7: [: ti: integer expression expected
./tst.sh: line 7: [: wi: integer expression expected
6

What do you want to do with those files?
If you are interested in just the filenames, a simple grep would do that !

$ grep '10[0-9][0-9]\.log$' file
/a/b/c/Daily/file1_20111012.log
/d/e/f/Monthly/file1_20111001.log
$

Do you have any specific requirement?

7

anchal_khare , It worked.

Can you tell why I got error with script?

Thanks to all, your replies are highly appreciated

8 
#!/bin/bash

[[ $# != 1 ]] && {
   echo "ERROR: No argument"
   exit 1
}

while read line
do
   [[ $line =~ $1 ]] && echo $line
done < /home/list.txt