how can i generate following sequence
for a given input 1,2,3,4,5
1->2
2->3
3->4
4->5
1->2,3
1,2->3
2->3,4
2,3->4
3->4,5
3,4->5
1->2,3,4
1,2->3,4
1,2,3->4
2->3,4,5
2,3->4,5
2,3,4->5
1->2,3,4,5
1,2->3,4,5
1,2,3->4,5
1,2,3,4->5
how can i make a use of shell script over here ?
Yes, trivial looping and arithmetic. Is this homework or ?
not homework exactly
it was challenge to me
Well, the first or critial number is generated in the outer loop, and the lines are generated inside using either arithmetic or another loop.
a=0
while (( ++a < 6 ))
do
b=$(( a + 1 ))
echo "$a->$b"
done
python script:
#!/usr/bin/python
mtn=[]
l=[]
def printSeq(n):
global l
l = range(1,n+1)
length = len(l)
global mtn
mtn = [str(x)+"->"+str(x+1) for x in l if x<l[-1]]
for x in mtn:
print x
for x in range(2, length):
print "" # empty line
for e in range(length):
if e+x< length:
generateOtherSeq(l[e:x+e+1])
def generateOtherSeq(myl):
for i in range(len(myl)):
ll = list(myl)
if i+1 < len(myl):
ll = mtn[l.index(myl)]
ll.remove(ll[i+1])
print ",".join([str(x) for x in ll])
printSeq(5)
you can change the last line "5" to any number you like. for example "7" will give you this output:
kent$ python pyseq.py
1->2
2->3
3->4
4->5
5->6
6->7
1->2,3
1,2->3
2->3,4
2,3->4
3->4,5
3,4->5
4->5,6
4,5->6
5->6,7
5,6->7
1->2,3,4
1,2->3,4
1,2,3->4
2->3,4,5
2,3->4,5
2,3,4->5
3->4,5,6
3,4->5,6
3,4,5->6
4->5,6,7
4,5->6,7
4,5,6->7
1->2,3,4,5
1,2->3,4,5
1,2,3->4,5
1,2,3,4->5
2->3,4,5,6
2,3->4,5,6
2,3,4->5,6
2,3,4,5->6
3->4,5,6,7
3,4->5,6,7
3,4,5->6,7
3,4,5,6->7
1->2,3,4,5,6
1,2->3,4,5,6
1,2,3->4,5,6
1,2,3,4->5,6
1,2,3,4,5->6
2->3,4,5,6,7
2,3->4,5,6,7
2,3,4->5,6,7
2,3,4,5->6,7
2,3,4,5,6->7
1->2,3,4,5,6,7
1,2->3,4,5,6,7
1,2,3->4,5,6,7
1,2,3,4->5,6,7
1,2,3,4,5->6,7
1,2,3,4,5,6->7