Gawk program not working in a script

Shell Programming and Scripting
1

I've written a very simple gawk program which runs when I execute it at the POSIX shell but the corresponding '.awk' script I wrote doesn't return
any data. I'm on an HP-UX running gawk version 3.1. (w/all the defaults)

(As you can probably guess I'm a newbie going through the manual and trying to execute the code samples).

I did write another script ( advice.awk ) and it works fine.

$cat find_li.awk
# searches file: mail-list looking for regexp "li" and reporting 2nd column
# (which is the phone number) if found
#! /usr/local/bin/gawk '/li/ { print $0 }' mail-list

$find_li.awk (this is the run of my script w/no results)
$

(Below is me running the commands in the script and it works fine)

$/usr/local/bin/gawk '/li/ { print $0 }' mail-list
Amelia 555-5553 amelia.zodiacusque@gmail.com F
Broderick 555-0542 broderick.aliquotiens@yahoo.com R
Julie 555-6699 julie.perscrutabor@skeeve.com F
Samuel 555-3430 samuel.lanceolis@shu.edu A

So - Why doesn't the script return any results?
(I did do the chmod +x find_li.awk )

2

well, it's because you commented out the command in a script:

# searches file: mail-list looking for regexp "li" and reporting 2nd column
# (which is the phone number) if found
#! /usr/local/bin/gawk '/li/ { print $0 }' mail-list

I think you meant this:

#!/usr/local/bin/gawk -f
# searches file: mail-list looking for regexp "li" and reporting 2nd column
# (which is the phone number) if found
/li/ { print $0 }

and have it call as find_li.awk mail-list

3

Thanks vgersh99. That solved it.:b: