What would be an accurate and efficient computation of the p-norm in Fortran?
Integer :: p
Real :: sum, pn
Do i = 1, Size (a)
sum = sum + ((Abs a(i)) ** p)
End Do
pn = sum ** (1.0/ Real(p))
What would be an accurate and efficient computation of the p-norm in Fortran?
Integer :: p
Real :: sum, pn
Do i = 1, Size (a)
sum = sum + ((Abs a(i)) ** p)
End Do
pn = sum ** (1.0/ Real(p))