finding the number of occurence of a word in a line

Shell Programming and Scripting
1

suppose i have this line

abs|der|gt|dftnrk|dtre
i want to count the number of "|" in this line..
how can i do that.
plz help:confused:

2

what have you tried?

3

i tried with grep..
grep -c "|" filename
but it is giving me the count of only the line number in which is pattern is present..i wnt to count the number of occurences of this pattern in a file

4 
echo "abs|der|gt|dftnrk|dtre" | sed 's/|/
>&/g' |  grep "|" |wc -l

echo "abs|der|gt|dftnrk|dtre" | awk '{ print gsub("\|","~",$0) }'
5

You can also use the '-o' flag for grep and then pipe it to wc

-bash-3.2$ echo "abs|der|gt|dftnrk|dtre" | grep -o "|" | wc -l
4
6 
 echo "|abs|der|gt|dftnrk|dtre|" | awk -F"|" '{print NF-1}'
7

thanx the last solution is working

8

Or delete every character except pipe, and count them.

echo "|abs|der|gt|dftnrk|dtre|" |tr -cd '|'|wc -c
9

but when i am trying it with a file then it is giving the separate output
like
5
5
5
5
5.

since the file contains five line and 5 "|" in each line
please help
i want total of the pipes in whole file:confused:

10

thanks i got it....:b: