Hi
I have a file named Employee and it has the following format:
File name:Employee
00000
0000:0000
YYNNN
20120302
NAME:010:C
ACCOUNT NUM:015,00:N
DATE:008,00:D
#DATA#
ROGER 00000002346123720120302
MAX 00000003654774020110612
JOHNSON 00000000000103420120713
#END#
0000003
How am going to get the displacements for a particular field say for example, I need to have the displacement of ACCOUNT NUM, the answer would be 11, because it starts at position 11. Likewise, I need to get the displacements of all fields in the following format:
Field Displacement
Name 1
Account Num 11
ID 26
Do we have any command which can get the desired output as shown above. Thanks..Appreciated your help.
pludi
March 5, 2012, 9:18am
2
Where are you pulling that data from? I can't see either of 1, 11, or 26 in the sample you provided.
Sorry for making you confused. Actually the length of the field is being specified in the data itself. Please find it(BOLD) below:
NAME:010:C (1-10)
Thanks
joeyg
March 5, 2012, 9:29am
4
How to determine though?
NAME:010:C (1-10)
ACCOUNT NUM:015,00:N (11-25)
DATE:008,00: D (26-33)
in a file by itself?
joeyg:
How to determine though?
NAME:010:C (1-10)
ACCOUNT NUM:015,00:N (11-25)
DATE:008,00: D (26-33)
in a file by itself?
No, (1-10) (11-25) (26-33) is not included in the file. Just for making it more clear, I have put it in a file. The actual data in the file is
NAME:010:C
ACCOUNT NUM:015,00:N
DATE:008,00: D
.
.
.
.
where 010, 015 and 008 are the lengths of the particular fields.
birei
March 5, 2012, 9:34am
6
Hi bobby1015,
One way:
$ cat infile
00000
0000:0000
YYNNN
20120302
NAME:010:C
ACCOUNT NUM:015,00:N
DATE:008,00:D
#DATA#
ROGER 00000002346123720120302
MAX 00000003654774020110612
JOHNSON 00000000000103420120713
#END#
0000003
$ cat script.pl
use warnings;
use strict;
die qq[Usage: perl $0 <infile> \n] unless @ARGV == 1;
my $displacement = 1;
printf qq[%s\t\t%s\n], qq[Field], qq[Displacement];
while ( <> ) {
my @f = split /[:,]/, $_;
next unless @f >= 2;
if ( $f[0] =~ m/\D/ && $f[1] =~ m/\A\d+\Z/ ) {
printf qq[%s\t\t%s\n], $f[0], $displacement;
$displacement += $f[1];
}
}
$ perl script.pl infile
Field Displacement
NAME 1
ACCOUNT NUM 11
DATE 26
Regards,
1 Like
Thanks a ton Birei..All i can say is a big WOWWWWWWWWW
---------- Post updated 03-06-12 at 09:26 AM ---------- Previous update was 03-05-12 at 09:49 AM ----------
Birei,
If I want to get the following output, How am I going to do it?
Field Displacement Length
NAME 1 10
ACCOUNT NUM 11 15
DATE 26 8
Thanks ..
birei
March 6, 2012, 9:37am
8
Try next script. Note that each field of output is separated with two tabs and seems weird. Change to your needs.
$ cat script.pl
use warnings;
use strict;
die qq[Usage: perl $0 <infile> \n] unless @ARGV == 1;
my $displacement = 1;
printf qq[%s\t\t%s\t\t%s\n], qw[Field Displacement Length];
while ( <> ) {
my @f = split /[:,]/, $_;
next unless @f >= 2;
if ( $f[0] =~ m/\D/ && $f[1] =~ m/\A\d+\Z/ ) {
printf qq[%s\t\t%s\t\t%d\n], $f[0], $displacement, $f[1];
$displacement += $f[1];
}
}
$ perl script.pl infile
Field Displacement Length
NAME 1 10
ACCOUNT NUM 11 15
DATE 26 8
$
Thank you so much.. Yea the ouput seems to be weird. Which part of the code do I need to change to make it(output) more clear.
birei
March 6, 2012, 9:48am
11
Like this (changes in red):
$ cat script.pl
use warnings;
use strict;
die qq[Usage: perl $0 <infile> \n] unless @ARGV == 1;
my $displacement = 1;
printf qq[%-20s %-20s %s\n], qw[Field Displacement Length];
while ( <> ) {
my @f = split /[:,]/, $_;
next unless @f >= 2;
if ( $f[0] =~ m/\D/ && $f[1] =~ m/\A\d+\Z/ ) {
printf qq[%-20s %-20s %d\n], $f[0], $displacement, $f[1];
$displacement += $f[1];
}
}
$ perl script.pl infile
Field Displacement Length
NAME 1 10
ACCOUNT NUM 11 15
DATE 26 8
Thanks a ton birei. Thats works well.
birei
March 6, 2012, 10:38am
13
Try:
$ cat script.pl
use warnings;
use strict;
die qq[Usage: perl $0 <infile> \n] unless @ARGV == 1;
my $displacement = 1;
printf qq[%s\n], join qq[,], qw[Field Displacement Length];
while ( <> ) {
my @f = split /[:,]/, $_;
next unless @f >= 2;
if ( $f[0] =~ m/\D/ && $f[1] =~ m/\A\d+\Z/ ) {
printf qq[%s,%d\n], join( qq[,], $f[0], $displacement ),$f[1];
$displacement += $f[1];
}
}
$ perl script.pl infile
Field,Displacement,Length
NAME,1,10
ACCOUNT NUM,11,15
DATE,26,8
1 Like
Birei, you are just AWSUM..Thank you soooooooooooooooooo much..