Finding part of a string

Shell Programming and Scripting
1

Hi I am very new to KSH programming
and need some help with finding a string in an error log

currently i am doing

cat FTP_LOG.lis | grep Warning

which gives me
Warning: Authentication failed. Remaining authentication methods: 'publickey,pas

I want to only pick up the test between the "Warning:" and the fullstop"."

Any help appreciated

cheers

DAF

2

Try something like this :

sed '/Warning/!d;s/.*\(Warning[^.]*\.\).*/\1/' < FTP_LOG.lis

Jean-Pierre.

3

here's one simpler, in Python:

for lines in open("FTP.lis"):
     if lines.startswith("Warning"):
         for c in lines:
              if c == '.': break
         print c,
4 
nawk -F '[:.]' '$1 == "Warning" { print $2 }' FTP_LOG.lis
5

Thank you
reborg, aigles and ghostdog74
for your isolutions, they work a treat

Cheers
DAF