finding files in Unix

Shell Programming and Scripting
1

Hi

1)How do i find files in unix that end either in .pc or .h

This does not return any output

find . -name "*(pc|h)"

2)I have a file like this
001123456
..

...

i want the output to be like
001-123-456 any tricks in regular expression can do this in vi.

regards
Hrishy

2

For your first question: find . -name ".ph" -o -name ".h"

3

As I understand, you want to change a file name from within vi.

:!mv 001123456 001-123-456
4

i interpret the second question as, the content of the file is 001123456 and you want to change this to 001-123-456 on each line ?
if this is the case and you are using vim, then you can record a macro for one line and then play it for rest of the lines. If you are using simple vi the following command may help you
:s/\(...\)\(...\)\(...\)/\1-\2-\3/g

5

Hi Linuxpenguin

Your understanding is correct.

But your answer has my head twirl what on the earth is that supposed to mean :-).Can you please dissect it for me.

regards
Hrishy

6

Hi RTM

Your code works like charm thank you

regards
Hrishy

7

Hi Hrishi,
ok, if you happen to read man page for sed or ed, you will get what it means. But I will go ahead to tell you what this one specifically means
:s ( search and replace)
/ pattern separator (you may use # or ? or some other characters as well, must / is most generic
\esacpe seq for (, where ( marks opening of block pattern ( i m not sure bt the term).
The . means any character, so ... means any 3 characters. so i make 3 blocks, with 3 characters each. they are autmatically marked as 1 2 and 3.
then the second / terminates the pattern to search for. so you have asked so far to search a pattern that has 9 characters, and you have grouped them in 3 groups of 3 characters each. Now you start to replace them, with what ? right, with each of the group separated by a -. so first group is \1, second is \2 third is \3. you can have upto 9 such grouped patterns (here i got the term :), it is called grouped patterns).
and then the last /g, means globally
so search a pattern of 9 characters, grouping them in groups of 3 of 3 characters each and replace them globally by the same grouped patterns separated by hyphen :slight_smile:
having said that, if you had more than 9 characters on the line, the rest would be neglected till there were 18, if you had 18, you wud have 6 groups, and so on. try playing with that and read some man page for sed. There is immense pattern help with sed.

8

Hi LinuxPenguin

Thank you very very much..dude you are awesome.

regards
Hrishy