Find Replace

Shell Programming and Scripting
1

Need to convert

echo "7 6"

to
$7,$6

But the count of numbers can increase say echo "7,6,8,9" tried this didn't work

echo "7 6" | sed 's/\([0-9]*\)/\1/'

But did not help much

2

why you dont have "$" in your replace string? Is that a typo?

/home-dev/->echo "7,6,8,9" | sed 's/\([0-9][0-9]*\)/$\1/g'
$7,$6,$8,$9
3

Something like this:

 
echo "4 5 6 7" | sed 's/[0-9][0-9]*/$&,/g'

Using awk:

 
echo "4 5 6 7" | awk '{ for(i=1;i<=NF;i++) $i="$"$i} OFS =","'
4

Thanks the awk did the trick i was so confused , i have to use nawk anyone know why awk some times fails but nawk works ?