Find problems

Shell Programming and Scripting
1

Hey,

I was hoping for some help, my point was to search for all "core" files with only digits in the extension

Eg:
1) core.153498 < He should find it
2) core.1 < He should find it
3) core.919jasj < shouldn't find it
4) core.abdijs < shouldn't find it

find . -name 'core.[0-9]*' -printf "%s \t %p \n" -type f

What am I doing wrong here?
He finds the first 3 examples and I just want it to find the first 2..

Thanks for your time,
Bruno

2

The only way I could see to get what you want is by using to separate find lines as below:

find . -name 'core.[0-9]' -printf "%s \t %p \n" -type f
find . -name 'core.[0-9]*[0-9]' -printf "%s \t %p \n" -type f

A scripting guru will no doubt come up with a one liner...

3

this will help you:b:

find . -type f -name "core.*" -ls -long|awk -F"\/" 'split($NF,A,".")A[2] !~ /[aA-zZ]/{print $NF}'
4 
$ ls core.*
core.1        core.153498   core.919jasj  core.abdijs
$ find . -name 'core.[0-9]*' -type f -print|grep "core\.[0-9]*$"
./core.153498
./core.1
5

You can change find's matching rules from glob to regular expression or if you prefer awk "-regextype posix-awk"

find . -regextype posix-egrep -name 'core.[0-9]*$' -printf "%s \t %p \n" -type f
6 
ls | egrep "core\.[0-9]+$"
7

That assumes all the files are in the same top level directory. But that gives this idea:

$ find . -name "core.*" -print
./abc/core.200
./abc/core.12xyz
./core.153498
./core.1
./core.919jasj
./core.abdijs
$ ls -R | egrep "core\.[0-9]+$"
core.1
core.153498
core.200

Assuming we don't have any directories startig with "core." otherwise we will have to add some more parts in the pipeline.