Find last occurrence of a character in a string

Shell Programming and Scripting
1

Hello

how to find last occurence of a string

for example in the following I want last occurence of '-' i.e. position 12

str="aa-bbb-cccc-ddd-ee"

my pupose is to get the string 'ee'

Thanks and Regards
Chetanz

2 
echo "aa-bbb-cccc-ddd-ee" | awk -F"-" '{print $NF}'
3

Many Thanks Pravin27

Sorry i misphrased the question

I got there but stumbled at getting last position

could you please advise how to get the "position" of last '-' in the string?

Thanks and Regards
Chetanz

4

here you go

echo "aa-bbb-cccc-ddd-ee" | awk -F"-" '{print length($0)-length($NF)}'
5

Assuming you're using a standards conforming shell (such as bash or ksh), this will also work:

str="aa-bbb-cccc-ddd-ee"
end=${str##*-}
echo "Last - is in column $((${#str} - ${#end}))"

and only uses shell built-ins.

With your sample string, it produces:

Last - is in column 16
6 
start=${str%-*}
echo ${#start}
15

This is OK, as the shell's string index starts with 0:

echo ${str:${#start}:1}
-