Find directory and create backup

Shell Programming and Scripting
1

What I'm attempting to do is create a script that will do a search for directories that meet the following criteria:

find . -name "config" -type d

this comes back with:

./dir1/anotherDir/test_dir/config
./dir1/anotherDir/test_dira/config
./dir2/test/test_dir/config

The results could be 10 directories or only 2, but once it comes back with the results I need to change directories to the parent directory of the config directory, then run

tar czf config.tgz config
/dir/to/another/script.sh config.tgz
mv config.tgz_new_file_name /backup/dir

I got most of it down, just the part where I want to CD to the parent directory of each result.

2

You could try wrapping the find command in a for loop. Not sure which OS or shell you're using but under Bash on Linux:

Save the starting directory:
export startdir="/dir"

Then loop:
for dir in `find . -name 'config' -type d`;do cd ${dir//.\//};cd ..;do your thing;cd $startdir;done

Breakdown:
${dir//.\//} will remove the leading ./ from the find output
cd.. will back up to the parent directory
cd $startdir will return to starting directory for the next iteration through the loop

Hope this helps point you in the right direction.

3

That works perfectly, now what if the search I'm doing is for a file.

find . -name file.txt;do ....;do my stuff;cd $startdir;done

4

I understand the {dir//.\//} removes the leading ./, but what would that need to be changed to when I'm searching for a file to remove the file name and the leading ./?

5

Forgot to mention it but I'm using SLES with Bash shell.