Find and replace a part of the word in Shell

Shell Programming and Scripting
1

I have a csv file in which there are numbers like

078976/9XXX
098754/8XXX

I want to replace the XXX with null. I want to know the command/code to do this.
I know how to replace the whole word/number. But don't know how to replace a part of it.

Thanks in advance,
Mihir

2

if you know its always going to be the last 3 characters,

 # echo "078976/9XXX"|sed 's/...$//g'
078976/9
3 
while read str
do
echo ${str%???}
done < file
4

Another way always with sed :

$ cat seqs.txt
999999/5
123456/1XXX
010101/22B12
$ sed 's!\(/[0-9]\{1,\}\).*$!\1!' seqs.txt
999999/5
123456/1
010101/22
$