Hi,
I had a input file containing,
abcdefghij;20100903040607;1234567891;GLOBAL;
abc123;20100903040607;12345;09;thestdf;
def456;20100903040607;67891;04;bnkim;
I need to search word GLOBAL in my file.
If it is found then
do something
else
do other thing
How can i write if loop for this criteria in .ksh file?
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Regards
I updated code with,
grep -i "GLOBAL" FILE
if [ $? -eq 0 ]
then
echo "grep successful"
else
echo "unsucessful"
fi
but receiving error as ,
grep: 0652-033 Cannot open FILE.
Please help me out to resolve this error.
What does this command tell you?
ls -l FILE
-rwxr--r-- 1 alf archive 45 Sep 27 11:21 MigBIOS.CR.GLOBAL.0100924021422.CSV
So your command is:
grep -i "GLOBAL" MigBIOS.CR.GLOBAL.0100924021422.CSV
and the error message is:
grep: 0652-033 Cannot open MigBIOS.CR.GLOBAL.0100924021422.CSV
Is that correct?
YES. Thats the one.
If ls -l FILE gives:
-rwxr--r-- 1 alf archive 45 Sep 27 11:21 MigBIOS.CR.GLOBAL.0100924021422.CSV
That would make "FILE" a directory?
I am writting this code into my shell script function which takes file name as command line agrument which then i stored in FILE variable.
FILE=$1
where $1 is MigBIOS.CR.GLOBAL.0100924021422.CSV.
Hi.
So, the grep should be grep -i "GLOBAL" $FILE
Now its working fine.
Thanks a lot.
Its my silly mistake 
Could you please let me know, how can I put the if loop condition for this?
if [ `grep -i "GLOBAL" $FILE` -eq 0 ]
then
echo "grep successful : GLOBAL"
elif [ `grep -i "PARTIAL" $FILE` -eq 0 ]
then
echo "grep successful : PARTIAL"
fi
Thanks in advance.
if grep -qi GLOBAL "$FILE"; then
echo "grep successful : GLOBAL"
elif grep -qi PARTIAL "$FILE"; then
echo "grep successful : PARTIAL"
fi
Thank you so much for your pro-active help. 
It's the filename itself.
