filtering text

Shell Programming and Scripting
1

Hi how can I filter the text using this one.
SAMPLE

 server[/]vmpool -listall|tail -11
================================================================================
pool number:  112
pool name:    Net-Ora-1wk
description:   Net-Ora-1wk
max partially full:    0
================================================================================
pool number:  113
pool name:    server1-data-3months
description:  server1-data-3months
max partially full:    0
================================================================================

server[/]vmpool -listall | grep data
pool name:    server1-data-3months
description:  server1-data-3months
server[/]

OUTPUT:
I want this to be the output:

pool number:  113
pool name:    server1-data-3months
description:  server1-data-3months
max partially full:    0

Or

pool number:  113
pool name:    server1-data-3months
description:  server1-data-3months
max partially full:    0

or

pool number:  113
pool name:    server1-data-3months
description:  server1-data-3months

My target is to get the pool number also..

2

Hi
Are you trying to say you want everything other than the "=================================================" line?

Guru.

3

yes, i want those 4 lines or 3 lines,,

---------- Post updated at 11:10 PM ---------- Previous update was at 11:04 PM ----------

also if you grep a test, how can you display the above and its below???
thanks

4

Hi

vmpool -listall | grep -v '^===='

Guru.

5 
server[/]vmpool -listall|tail -11
================================================================================
pool number: 112
pool name: Net-Ora-1wk
description: Net-Ora-1wk
max partially full: 0
================================================================================
pool number: 113
pool name: server1-data-3months
description: server1-data-3months
max partially full: 0
================================================================================

server[/]vmpool -listall | grep data
pool name: server1-data-3months
description: server1-data-3months
server[/]

---------- Post updated 06-21-10 at 03:50 AM ---------- Previous update was 06-20-10 at 11:18 PM ----------

Hi, any update please?? I just want that everytime i grep or search for a test, i can get the line above and the line below.
thanks

for example.

#cat file1.txt
yoh yoh
data1
server
base
12345
save

the output should be like this, how??

#grep server file1.txt
data1
server
base
6

Does your grep know the -C option?

#grep -C1 server file1.txt
data1
server
base
7 
vmpool -listall|grep -Cl
grep: Not a recognized flag: C
Usage: grep [-E|-F] [-c|-l|-q] [-insvxbhwy] [-p[parasep]] -e pattern_list...
        [-f pattern_file...] [file...]
Usage: grep [-E|-F] [-c|-l|-q] [-insvxbhwy] [-p[parasep]] [-e pattern_list...]
        -f pattern_file... [file...]
Usage: grep [-E|-F] [-c|-l|-q] [-insvxbhwy] [-p[parasep]] pattern_list [file...]

---------- Post updated at 04:16 AM ---------- Previous update was at 04:15 AM ----------

[/COLOR]

vmpool -listall|grep -C1 di
grep: Not a recognized flag: C
grep: Not a recognized flag: 1
Usage: grep [-E|-F] [-c|-l|-q] [-insvxbhwy] [-p[parasep]] -e pattern_list...
        [-f pattern_file...] [file...]
Usage: grep [-E|-F] [-c|-l|-q] [-insvxbhwy] [-p[parasep]] [-e pattern_list...]
        -f pattern_file... [file...]
Usage: grep [-E|-F] [-c|-l|-q] [-insvxbhwy] [-p[parasep]] pattern_list [file...]
8

Alright, try these in that case:

Awk:

awk '/server/{if(p) print p; print; if(getline) print}{p=$0}' infile

Sed:

sed -n '/server/{x;1!p;g;$!N;p};h' infile
9 
awk '/server/{if(p) print p; print; if(getline) print}{p=$0}' infile

that line works for me,, thanks a lot...great help..

---------- Post updated at 04:43 AM ---------- Previous update was at 04:43 AM ----------

the sed was not working...thanks..really..

10 
awk ' /server/ { ME=$0;getline; printf("%s\n%s\n%s\n",NI,ME,$0) } { NI=$0 }'  file.txt
11 
vmpool -listall| grep -v "===*"

this will work. (-v option displays all the line which doesnt have that specific pattern"

12

Slight improvement: this also works like grep -C1 for consecutive matches:

awk '{if(/Asterix/){if(p&&!n)print p; print; n=1} else if(n){print;p=n=0} else{p=$0}}' infile
13

Hi Scrutinizer,
Your last reply is the most accurate however your prevoius answer on awk is suffice...

vmpool -list_all|awk '/CU/{if(p) print p;print; if(getline) print}{p=$0}'

vmpool -listall| awk '{if(/CU/){if(p&&!n)print p; print; n=1} else if(n){print;p=n=0} else{p=$0}}' ---> in this command i was able to get the whole details...thanks...

care to explain them??? the if??? p&&n getline etc??

thanks a lot