filter data

Linux and Unix-Like Linux
1

hi all,

here is my question.
i have the following data

Block 1

a    b    c
d    e    f
g    h    i

Block 2

j    k    l
m    n    o
p    q    r

i need to grep all information from block 1 i.e 'a to i'

should i count the number of row, can somebody help me on this,

thanks

2

What is the use of Block 2 ?

3 
$ ruby -00 -ne 'print if /Block 1/' file
4

thanks for reply,

well block 1 & 2 are examples, actually i have a very large file container information and i need to filter them by row i have 11 row to filter.

5

hi

is the pattern you are grepping for always going to start with a and end with i?

Then Please try

sed '/start point/,/end point/!d' file.txt

ie

sed '/a/,/i/!d' file.txt
6

no it does not alway start with the same character mentioned.

i want to user the first character or word on the 1st row and count x numbers of row and then print the result

7

Borrowed this from some post ( sorry cant remember).

For greping/searching and displays a lines before and b lines after context

  

  nawk 'c-->0;$0~s{if(b)for(c=b+1;c>1;c--)print r[(NR-c+1)%b];print;c=a}b{r[NR%b]=$0}' b=2 a=4 s="string" file1

...where "b" and "a" are the number of lines to print before and after string "s".