Extrct IP from ping

Shell Programming and Scripting
1

Hi guys,
I'm looking for a script to extract the IP address reported by the command:

$> ping -c 1 192.168.1.254
PING 192.168.192.254 (192.168.192.254) 56(84) bytes of data.
64 bytes from 192.168.192.254: icmp_seq=1 ttl=64 time=139 ms

--- 192.168.192.254 ping statistics ---
1 packets transmitted, 1 received, 0% packet loss, time 0ms
rtt min/avg/max/mdev = 139.136/139.136/139.136/0.000 ms

What I have to get is the value after the "64 bytes from" and only the reported IP not the data after the ":".

In my real case the ping will be executed on broadcast address as 192.168.192.255.

I'm using a BASH script.
Thanks in advance

2

play around with grep/awk and you'll have a solution
$ > ping -c 1 192.168.1.254 | grep "64 bytes from"|awk '{print $4}'

3

You can also check with nmap whole network

nmap -sP 192.168.1.1-254 | grep Host | awk '{print $2}'

Regards,
Bash

4

For single query of ping

ping -c 1 192.168.1.156 | grep "64 bytes from " | awk '{print $4}' | cut -d":" -f1

192.168.1.156

Regards,
Bash

5

Your example show the Useless Use of grep and cut when awk can do all.

ping -c 1 192.168.1.156 | awk -F" |:" '/from/{print $4}'

Regards,
Dan

6

With awk only:

ping -c 1 192.168.1.254 | awk -F'[ :]' 'NR==2 { print $4 }'
7

Hi Dan,

I just gave the alternate method, as you see that was my second reply, but any way thanks for your comments.

Regards,
Bash

8

No problem, we just try to find the best/fast solution.

Regards,
Dan

9

Many thanks to everyone for suggestions