Extracting file name from path

Shell Programming and Scripting
1

if I have a variable value "filetoprocess" equal to "/aaa/bbb/ccc"

How can I simply extract the file name of "ccc"

2 
filename=${filetoprocess##*/}
3

Hi Franklin,

could you please explain the solution?

thanks in advance.

4

I can't explain it better then this:

Learning the Korn Shell, 2nd Edition: Chapter 4: Basic Shell Programming Pattern-Matching Operators

:cool:

5

You could also use basename.

basename "/aaa/bbb/ccc"

or to put it in a variable

filename=`basename "/aaa/bbb/ccc"`