Extract the uptime from the output of the uptime command

Shell Programming and Scripting
1

Hi!

I want to extract the uptime from the output of the uptime command.

The output:

11:53  up  3:02, 2 users, load averages: 0,32 0,34 0,43

I just need the "3:02" part. How can I do this?

Dirk

2 
echo $(uptime) | sed 's/^.\+up\ \+\([^,]*\).*/\1/g'
3 
uptime | awk '{print $3}'
4

I think this works only if uptime < 1 day :wink:

5

Right, thanks, it should be something like:

uptime | awk -F, '{sub(".*up ",x,$1);print $1}'
6

Here's a couple more "uptime" examples to play with.
They are UK number format (unlike the O/P who has a comma as a decimal separator).
Note that the format increases the number of comma-separated fields and also changes if the uptime is an exact number of hours.

 12:55pm  up 105 days, 21 hrs,  2 users,  load average: 0.26, 0.26, 0.26
  1:41pm  up 105 days, 21:46,  2 users,  load average: 0.28, 0.28, 0.27

It can be done by converting commas to newlines and ignoring everything from the line containing "users". My trial script got too convoluted to post!

7 
>> uptime | awk -F, '{sub(".*up ",x,$1);print $1}'

Exp-

# uptime
11:29:16 up 47 days, 20:34,  2 users,  load average: 0.01, 0.01, 0.00

# uptime | awk -F, '{sub(".*up ",x,$1);print $1}'
47 days

It lists only days but there is no output for hours 20:34. So there is little modification:

# uptime | awk -F, '{sub(".*up ",x,$1);print $1,$2}'
47 days  20:34