extract lines from text after keyword

I have a text and I want to extract the 4 lines following a keyword!

For example if I have this text and the keyword is AAA

hello
helloo
AAA
one
two
three
four
helloooo
hellooo

I want the output to be

one
two 
three 
four

if your grep supports -A option, then use it like

grep -A 4 "AAA" file.txt

else, you can try with awk

awk '/AAA/{for(i=1;i<=4;i++){getline;print}exit;}' file.txt

with this code I get the line with the keyword too! I dont want this line!

Try:

awk 'p-->0; /AAA/{p=c}' c=4 infile

thank you! it works great!
if it's not trouble do you know how can I do this with grep?

AFAIK this cannot be done with grep alone...

ok! thnx again for the info

If the keyword appear only once:

sed -n '/AAA/{n;N;N;N;p;q}' infile

otherwise:

sed -n '/AAA/{n;N;N;N;p}' infile