Extract lines from a file automatically. Please a Help

Shell Programming and Scripting
1

hello, hope you can help me:
ive got a file called archivos

The content or structure of this file is

./chu0/filechu
./chu1/filechu

I extract each line from this file manually and redirect to a file, and it Works fine, so the command line is:

awk �/chu0/ {print $0}' < archivos > portal0
awk �/chu1/ {print $0}' < archivos > portal1

The problem is to extract these lines automatically, an i dont know how to do this, with a loop for example.

and i tried but gets some error whit this command

i=0
while (i<=num)
do
awk -v i=$i � /chu$i/ {print $0} < archivos > portal$i
done

how can i do that so i can extract lines from this file automatically?can you help me? please.

2 
#!/bin/ksh

while read myLine
do
  echo "line-> [${myLine}]"
done < archivos
3

Thanks for yor reply, but in this script how the code will be in born shell.?

4

try it as 'bourne' and see what happens.

5

This code lnly print the output on the screen:

line-> [./chu0/filechu]
line-> [./chu1/filechu]

But, i want is to redirect the content of each line to a file
i.e. file0 the content must be ./chu0/filechu
and file1 the content must be ./chu1/filechu
thanks

6 
#!/bin/sh
i=0
while read myLine
do
  echo "${myLine}" > "file${i}"
  i=`expr $i + 1`
done < archivos
7

Could you please comment each line what it does?. i am new at unix, why you quote some lines.
Thanks again.

8

Hello
Thas working, but to be sincere dont undesrtand so much

ie what some lines have curly braces and double quotes, why?

9

try reading the man page for sh.

Spectificall the sections on Parameter Expansion and quoting.