Exit from function

Shell Programming and Scripting
1

Hi,

I just want to exit from function if some condition doesnt meet then control should go back to main program and start running from where it left..

When i used "exit" inside the function, its simply exited from entire script and it didnt run anymore.. Any idea how to do this..

Thanks in advance!

2

use return.

3

Please check the below sample code...

$ cat fun.sh
Menu ()
{
echo -n "Enter a positive number:"
read a
Greater
}
####
Greater ()
{
if [[ $a -gt 0 ]]
then
echo "$a is Positive number"
else
echo "Entered number is not a positive"
Menu
fi
}
Menu

OUTPUT:
$ ./fun.sh
Enter a positive number
-2
Entered number is not a positive
Enter a positive number
-2
Entered number is not a positive
Enter a positive number
-2
Entered number is not a positive
Enter a positive number

Thanks

4 
Menu()
{
        stat=1
        while (( stat != 0 ))
        do
                echo -n "Enter a positive number:"
                read a
                Greater "$a"
                stat=$?
        done
}

Greater()
{
        num="$1"
        (( num > 0 )) && echo "$num is Positive number" && return 0
        echo "Entered number is not a positive"
        return 1
}

Menu