exit a shell script!!

Shell Programming and Scripting
1

could somebody tell me please how to exit a shell script:

if [ $# -eq 0 ]
then
echo "No arguments detected"
exit 1
fi
...
echo "still there" # is displayed .. :frowning:

2 
if [ $# -eq 0 ]
then
echo "No arguments detected"
exit 1 #exit shell script  
fi
...
echo "still there" # is displayed .. :-(
3

sorry...... I have the following situation and it does not work :frowning: :

if [ $# -eq 0 ]
then
usage()
fi

echo "still there.."

usage {
echo "No arguments detected"
exit 1 #exit shell script
}

4

Try this..

function  usage {
echo "No arguments detected"
exit 1 #exit shell script
}
if [ $# -eq 0 ]
then
usage
fi

echo "still there.."
5

Function must be declared before it is used in script.try the below script..

usage ()
{
echo "No arguments detected"
exit 1 #exit shell script
}

if [ $# -eq 0 ];
then
usage
fi

echo "still there.."