How to find a word in a directory which contains many files?
i just want to count how many such words are present in all the files?
This is the code which i tried for a single file
echo "Enter the file name:"
read file
echo "Enter the word to search:"
read word
if [ -f $file ]
then
echo "The count is :"
grep -o $word $file | wc -l
else
echo "The word doesn't exist"
fi
The grep command has the -c flag to help you count without needing to pipe the output to the wc command.
Do you want to search all files in a particular directory? What about subdirectories?
Kind regards,
Robin
i just need to print the counts for each file in a directory
how can i execute this using for loop?
in my case there is no subdirectory
---------- Post updated at 07:46 PM ---------- Previous update was at 07:43 PM ----------
echo "Enter the word to search:"
read word
for (( i=1; i<=10; i++ ))
do
if [ -f $file ]
then
count=grep -o $word $file | wc -l
echo "$i '/t' $file '/t' $count "
else
echo "The word doesn't exist"
fi
done
Hi
What is the use of loop to check 10 times and if condition ?
Try below one:
grep -o -c $word *
If you have subdirectory or files under it then add -r option.
So to loop for each file in the current directory it is like this:-
for file in *
do
echo "Working on $file" # Whatever you need to do to each file here
done
To count the occurrences of $word you can use the line:-
grep -co $word $file
If you want the total for all the files in the directory, you might get away with (no loop required):-
grep -co $word *
You might have to merge all the files together to avoid getting individual file counts (again, no loop):-
cat *|grep -co $word
I hope that this is useful,
Robin