executing commands in remote server using ssh

Shell Programming and Scripting
1

I have some commands which need to be executed in remote machine.

I have Linux Server from where I need to connect to Solaris server using ssh and then declare some variable over there and run some commands. I don't want to call a script which is present in Solaris server from Linux server rather I want to execute commands in remote machine. Please help asap.

2 
ssh machine_name "ps -ef"
3

As you have mentioned about declaring variables and executing commands, this will help

ssh user@hostname "a=\"ls -l\"; $a"
4

But I have written many commands ,doing that will be very hectic .pls suggest some easy way

5

what do you mean "written many commands"

if you are having list of commands to be executed, then use a script, other wise using this ssh could be hectic.

6

many commands means i have written a script .I want instead of executing that script I want that commands present inside the script should be executed.

7

If you want so, then as i have posted, execute your commands one by one by seperating them with semicolon.

8

I think this is what you want. It's one inline script calling a ksh which has two parts, the one surrounded by double quotes (") gets expanded on the local machine, allowing remote $variables to be set, then the second part is surrounded by single quotes (') which does not get expanded locally so you can use remote variables such as the $file one shown.

I think it looks quite clean, readable and self contained and you can quite a lot of commands run in the single quote section.

echo "OUTPUT"
dir="/tmp"
mask="*.tar"
ssh -n $USER@$MACHINE /bin/ksh -c ":
        # this part gets expanded locally so use only to pass in variables
             dir='$dir'
     mask='$mask'
"'
     # This gets run remotely do not use single quotes
             echo "using single quotes ('\'') is tricky"
             echo "searchng: $dir; for $mask;"
     cd "$dir"
     pwd
             for file in $(ls -t $mask); do
                         echo "found: $file"
            done
'
OUTPUT
using single quotes (') is tricky
searchng: /tmp; for *.tar;
/tmp
found: Another.tar
found: Save.tar