execute multipe commands

Shell Programming and Scripting
1

I would like to execute multipe commands in a shell script. Please provide the commands for the below scenario:

Execute command1
if command1 is succesfull, then execute command2, command3,command4 in parallel
if command2, command3,command4 are success then run command 5

1 Like
2

with echo $? , you can get the exit status, if above command is successful, it should be 0.

command1
if [ $? -eq 0 ] then
  command2;commend3;command4
  another if-then-fi
fi

You can also add the exit status directly in script to control your condition.

3

Not as clean as rdcwayx but just to show various options and can be handy at the prompt.
You can use logical operator && after each command.
The shell executes the second command -- if and only if -- the first command returns a true (zero) exit status.

Example:

 command1 && command2 && command3 && command4 && command5

The above states if command1 is successful execute command2 if command2 successful execute command3 and so on.

Regards,
SRG

4

OP wanted to run jobs in parallel.

I created a dummyjob script like this:

sleep $1
exit $2

And the used array to store PIDs of the child processes and then waited for each of them and stored first non-zero exit status:

if ./dummyjob 4 0
then
    ./dummyjob 10 0 &
    j[0]=$!
    ./dummyjob 4 7 &
    j[1]=$!
    ./dummyjob 2 0 &
    j[2]=$!
    FAIL=0
    for PID in ${j
[*]}
    do
       wait $PID || FAIL=$?
    done
    echo "Result $FAIL"
else
   echo "First Job failed"
fi

Output appeared 14 seconds after job started:

Result 7