Error while executing sh command

Shell Programming and Scripting
1

Hi,
I have 2 files temp1.sh and temp2.sh as follows:

temp1.sh

echo "session1"
sh temp2.sh
echo "exit session2 and enter session1"

=================================

temp2.sh

echo "session2"
sh 
echo "exit session2"

=================================
when i execute the temp1.sh script file (sh temp1.sh)
i need the output as

session1
session2
exit session2
exit session2 and enter session1

=============================
but i get the output as

session1
session2

==============
After executing "sh" line in temp2.sh, it is coming out from the parent script(temp1.sh)Please help me on this....
thanks!

2

Is there any use of the sh command inside the temp2.sh ? If not remove that one and run the script.

3

sh without any arguments will read commands from stdin. If you have not redirected stdin, it's waiting for your input at the terminal. Typing control-d will send EOF (end of file) and sh will exit, resuming the script.

Aside from possibly executing some startup files, sh < /dev/null should not do anything at all; when it attempts to read a command from stdin, it immediately sees EOF. Seems rather pointless.

Regards,
Alister

4

As alister explains, the free-standing sh has started a clean interactive shell. To get out of it, type exit or the control code for end-of-file (usually ctrl/D ) .
See stty -a to find out the control code for end-of-file on ypur terminal.

5

Thanks for the replies!..

"command sh" is used to create a trusted sesion ID (which is called from .exe)to execute a batch file.. so sh command is necessary and cannot remove that line..is there any other way to get the exact o/p?(the code given above is just a dummy code..actual code is different)

6

I have no idea what you're talking about. "Dummy code" is usually a waste of everyone's time.

Regards,
Alister