error in ksh script

Shell Programming and Scripting
1

Hi,

i am facing an error in the following script in the korn shell but in bash it is working , can any help me to convert the below script to korn shell script without errors.

          echo 123.4566 | bc -l | awk -F '.' '\{ print $1; exit; \}'

Thanks in advance
kamal

2

I got 123 as an answer, no error. :slight_smile:
I ran it on HP-UX in a script starting with #! /usr/bin/ksh
Ans also on the commandline were echo $SHELL was the ksh.

What error do you get? :confused:

3

the form me it has shown was ,
awk: syntax error near line 1
awk: bailing out near line 1

4 
$ echo 123.4566 | bc -l | awk -F '.' '{ print $1; exit; }'
awk: syntax error near line 1
awk: bailing out near line 1

$ echo 123.4566 | bc -l | awk -F. '{ print $1 }'
123

And, of course, all you need is:

$ typeset -i n=123.4566;print $n
123
5

how to round it to near value....
if it is 123.999, then how to make it 124 using scripting in ksh

6

It seems you're using ksh88 (a Korn shell implementation that does not support floating point arithmetic).
So you can try something like this:

$ unset n
$ n=123.333                                                             
$ _n=${n#*.};((${_n%${_n#?}}>=5))&&print $((${n%.*}+1))||print ${n%.*}
123
$ n=123.666                                                             
$ _n=${n#*.};((${_n%${_n#?}}>=5))&&print $((${n%.*}+1))||print ${n%.*}
124