egrep problem | printing next line?????

Shell Programming and Scripting
1

Hi !!! Dear People,
Please help me with the following problem.
consider this output:
Top 5 Timed Events

Event                                               Waits    Time \(s\) Ela Time
---------------------------- ------------ ----------- \-----
CPU time                                                           2,152    54.10
free buffer                                           7,059         641    16.10
control file parallel write                        19,625         490    12.31
log file sync                                         7,010          217     5.44
db file sequential read                            3,000        1000      .99
\--------------------------------------------------------
we all know ,if i give 
egrep '^\(log file sync\)...' /oracle/user_user/2
it will print 
log file sync                                         7,010          217     5.44
please tel me how to print next line using egrep.
meaning... it should print immediate next line of pattern matching character\(here it's log file sync\).
my desired output should be 
db file sequential read                            3,000        1000      .99

perhaps with the same pattern matching character

please help me to give the command.
im using default shell\(-sh\)

Thanks in Advance
2

Line before is "-B", "line after" is "-A". One line after is "-A1", see 'man grep'.
If you want to see only the next line you could pipe that through 'tac|head -1'.

3

hay it's not working.. please give me full code......

4 
awk '/^log file sync/{getline;print;exit}' file

Regards