egrep help

Shell Programming and Scripting
1

hi,

i'm using egrep -i to search thru some text files for keywords (also stored in a file).

egrep does wildcard search aka %keyword%
as long as the keyword is found, it will be spool to a file
meaning if keyword is 'xyz'

123 aabgdggjxyzslgj
124 xyzgjksgjd

returns

123 aabgdggjxyzslgj
124 xyzgjksgjd

how do i make egrep search for keyword% only.
meaning if keyword is 'xyz'

123 aabgdggjxyzslgj
124 xyzgjksgjd

return only '124 xyzgjksgjd'

Can i add some indication to egrep in the keyword too? i tried egrep -i '^xyz' but in vain

2

Can't you place a space before the pattern like this?

egrep ' xyz' file
3

doubt tat,

it returns everything. :smiley:

4

Post a more realistic example and the desired output.

5

here it goes:

keyword file contains

xyz
abc

compressed data file (file1.gz)contains

p1 123 ljojeojo
p2 124 ighsphabc
p3 125 xyzskjkejhoj
p4 126 jorjojojojojo
p5 127 XYZrgjeojho
p6 128 gigsekxyz

i first read the keyword file

then using gzcat "file1.gz" | egrep -i $(searchitem) >> file1.out

to return

p3 125 xyzskjkejhoj
p5 127 XYZrgjeojho

by putting a '^xyz' can return results only if the 1st 2 columns are not present.
:smiley:

6

I don't see why Franklin's solution should not work.
f1 is the pattern list, f2 the file to search in:

$> while read F1; do grep -i " $F1" f2; done < f1
p3 125 xyzskjkejhoj
p5 127 XYZrgjeojho
7 
egrep -i " $(searchitem)" >> file1.out

or

egrep -i "[ \t]$(searchitem)" >> file1.out
8

From your given input we could try..

egrep -i '[0-9][0-9]* xyz*'
9

thanks for all the input,

this will do 'xyz' but for 'abc'

i would like to do a '%abc%' instead of 'abc%'.