echo problem

Shell Programming and Scripting
1

Hi,

I have given the following statement in a script to put the values of variables (VAR1, VAR2,...) in a file.

echo " $VAR1 $VAR2 $VAR3 $VAR4 $VAR5" >> filename

But the output is not coming properly. Variables VAR5, VAR4 are replacing the first (VAR1, VAR2,..). I can't figureout the reason. Say

VAR1=50; VAR2=51; VAR3=52; VAR4=53; VAR5=54;

Output: 53 54 52 (Something like this)

But if you echo each variable separately it is echoing properly.

Can anyone help me on this ?

Thanks
Ben

2

Hi,

Your scripts works fine, didn't encounter the problem u mentioned. Not sure why u have such problem. I just test out these two sentences. Look at your syntax again. u must have put the variable in echo at the wrong order.

VAR1=50; VAR2=51; VAR3=52; VAR4=53; VAR5=54;

echo " $VAR1 $VAR2 $VAR3 $VAR4 $VAR5" >> testtest

3

If we assign values then it would work fine.

But if we get values from files & then echo them there'll be problem.

Ben

4

hello..

For me ..its working fine...even assigning values during execution..
please check the code once more. there might me some other problems

regards
esham

5

try putting tabs in between the varaibles

echo " $VAR1\t $VAR2\t $VAR3\t $VAR4\t $VAR5\t" >> filename
6

Just a note that some versions of echo (notably Linux) require the "-e" option to enable interpretation of backslash-escaped sequences, e.g.

echo -e "blah\tblah\tblah"

Cheers
ZB