Echo escaped \c in SH Shell Any Idea

Shell Programming and Scripting
1

Hi All,

I have got an echo statement with "\c" in it to avoid getting into a newline. Ths script is using #!\bin\sh

Any idea what could make it to escape "\c"

2

Perhaps you can use:
print -n

bye

3

You are breaking the rules by bumping up posts. Moderators, please merge this thread with Which SHELL is this ?

You havent shown us what command you issued. Without that we cant help you.

Try reading the man pages as well. They have documented the use of \c very well.

See this.

[/tmp]$ cat try.sh
#! /bin/sh

echo -e "Line 1\c"
echo ""
echo -n "Line 2"
[/tmp]$ ./try.sh 
Line 1
Line 2[/tmp]$

From man sh

       echo [-neE] [arg ...]
              Output the args, separated by spaces,  followed  by  a  newline.
              The return status is always 0.  If -n is specified, the trailing
              newline is suppressed.  If the -e option is  given,  interpreta-
              tion  of  the following backslash-escaped characters is enabled.
4

i am sorry, i just forget that i have mentioned this question in my other thread which actually started with another question

echo "adbcd \c"

echo -n "abcd"

Both are working for SH and BASH respectively, but at Production site i don't know what has happened wrong that is causing \c to escape.

5

Thanks Folks for your Patience (sorry for my quick posts)

echo is most inconsitent thing. There is a SYSV3 variable on Unix which tends to change the behaviour of echo command or shell-builtin.