Do while loop in a do while

Hi,
I've a script that is using do while loop. It reads some some stuf using ps command then calls a function. The function has another do while loop in it.
My problem is that when the second loop is completed, the script exits. The whole thing is a bit complex, I'll post some snippet here. Any suggestions will be appreciated like always.

TELNET_QUIT=/tmp/telnet_quit.tmp  # file for telnet sessions.  Suppress on screen display
TELNET_LOG=/tmp/telnet_`date +%Y-%m-%d`.tmp
TELNET_TEST=NULL
echo "QUIT">$TELNET_QUIT

function telnetTest {
 	echo "  Please wait. "
	while read -r -u3 LINE1; read -r -u4 LINE2;
		do
		telnet  $LINE1 $LINE2 <$TELNET_QUIT >$TELNET_LOG 2>&1
		wait $!
		TELNET_TEST=$(grep "Connection closed by foreign host." $TELNET_LOG | wc -l)
		if (($TELNET_TEST)); then
		   echo "  OK. $LINE2" >>/tmp/somelog
		else
		   echo "  Problem! $LINE2" >>/tmp/somelog
		fi
		sleep 4
		more $TELNET_LOG >>/tmp/somelog
	done 3< "$TMPFILE" 4< "$TMPFILE2"  # Works till here, then exits out completely 
} # End of function

function getmyInfo  {
# We get my_SERVERS_NUM value from some where� snip 
my_SERVERS_NUM=1  # hard coding for one only
my_SERVER=10.10.10.10
TMPFILE=/tmp/tmp1.out
echo 10.10.10.10>$TMPFILE
my_SERVER_PORT=9120
TMPFILE2=/tmp/tmp2.out
echo 9120 >$TMPFILE2

if [ $my_SERVERS_NUM -ge 2 ]; then
	echo "  Many servers to check. " 
	telnetTest
else
	echo "  Only one server to check. "
	telnetTest
fi
}  # End of function

ps -ef |  awk '/[m]yAgent/{print $8}' | while read lines ;
	do
    		set -- $lines
		my_PATH=`echo $lines | sed '$s/myAgent.bin$//'`
		echo -n "  Analyze this instance (y/n)? " 
		read answer</dev/tty
		if [ "$answer" = y ]  ; then	
		my_pid=`ps -ef | grep $line | grep -v grep | awk '{print $2}'`
		getmyInfo
		fi
	done

#some cleanup stuff
#EOF

Thanks for looking.

Nitin

It's probably the more command it reads stdin - try using cat instead.

I thought so too, but the reads on the while are reading from fd3 and fd4 and not stdin. I could be wrong, but I did pull down the code I couldn't get it to break.

Maybe adding set -x at the top of the script with the hope that the trace info might provide a clue as to what is happening.

Might also help to know which shell and operating system.

This loop:

ps -ef |  awk '/[m]yAgent/{print $8}' | while read lines ;

is using stdin so anything called from within it (like telnetTest()) cannot use any process that opens (and closes) stdin.

I feel stupid -- I had set all of the tmp files to a different directory which was failing and my test never got to the more. Grrrrrr. Fixed my bug and problem reproduced, changed more to

 cp $TELNET_LOG /tmp/somelog

and no problem.

@Chubler_XL -- thanks for making me look harder at this. Hope OP sees it now.

I'll try the your suggestion.
Thanks.

Thanks to all, you guys are great. The cat command seem to have worked. I could not use cp, as I was pushing lots of output from other areas to the log. Here is the snippet of my telnet function.

 function telnetTest {
 	echo "  Please wait. "
	while read -r -u3 LINE1; read -r -u4 LINE2;
		do
		telnet  $LINE1 $LINE2 <$TELNET_QUIT >$TELNET_LOG 2>&1
		wait $!
		TELNET_TEST=$(grep "Connection closed by foreign host." $TELNET_LOG | wc -l)
		if (($TELNET_TEST)); then
		   echo "  OK. $LINE2" >>/tmp/somelog
		else
		   echo "  Problem! $LINE2" >>/tmp/somelog
		fi
		sleep 4
		cat $TELNET_LOG >>/tmp/somelog
	done 3< "$TMPFILE" 4< "$TMPFILE2"  
} # End of function

Sorry to jump in, and a bit off topic.
However I always thought that in order to use the wait $! syntax below:

wait $!

You would have to put the command into the background using the ampersand

2>&1 &

.
Does sending the stdout and stderr to a file constitute the proper usage for wait?

telnet  $LINE1 $LINE2 <$TELNET_QUIT >$TELNET_LOG 2>&1
		wait $!
		TELNET_TEST 

jaysunn

Hadn't noticed that before, but you are right; there'd be nothing to wait on since nothing was run asynchronously.

I think I'll try the &. Good catch.