Display string at line number

Shell Programming and Scripting
1

I have a code here , which should display lines 6,10,14,18,35 of a text file

 
#!/bin/ksh
line[1]=6
line[2]=10
line[3]=14
line[4]=18
line[5]=35
for i in 1 2 3 4 5
do
val=`echo ${line[$i]}`
act=`awk 'NR~/^($val)$/' db_CHECKOUT.txt`
done;

This code is not working. The purpose of the line below is to grep for line 6 from the file db_CHECKOUT.txt. It works fine when it has a number bt when i replace a variable "%val" in the above code its doesnt give any result

 
awk 'NR~/^(6)$/' db_CHECKOUT.txt
2 
act=`awk 'NR~/^("'"$val"'")$/' db_CHECKOUT.txt`

or

act=`awk 'NR~/^(v)$/' v=$val db_CHECKOUT.txt`
3

Thanks for the reply..I replaced the code with the line that you posted ..Its displaying 5 blank lines...although my text file has data on each line

4

Perhaps this might work for you (as a replacement for you script)?

sed -n '6p;10p;14p;18p;35p' infile

or

sed -ne6p -e10p -e14p -e18p -e35p infile