Disk Quota Exception while deleting the files

Shell Programming and Scripting
1

This is the full file name I get when I do ls -lt from my current directory.

EXPORT_v1x0_20120811_11_T_065800_070000.dat.gz

File names also consist of date as well. In the above file date is 20120811.

So I am trying to delete all the files which starts with EXPORT_v1x0 and whose date is less than 20120825.

I am using the below script from the command line to delete the files

    find . \( ! -name . -prune \) -type f -name "EXPORT_v1x0*" | awk -F'_' '$3<20120825' | xargs rm

But whenever I use the above command to delete the files, I always get this below exception.

    rm: ./EXPORT_v1x0_20120811_11_T_065800_070000.dat.gz not removed: Disc quota exceeded

Can anyone tell me what does this exception means? And how to overcome this problem?

I am running SunOS.

  bash-3.00$ uname -a
    SunOS lvsaishdc3in0001 5.10 Generic_142901-02 i86pc i386 i86pc
2

Check this thread and try the solution provided by jim mcnamara

3

Thanks for the help But should I add that truncation part in my script here? That's confusing me a lot.

4

> $fname is the truncation part. Just modify the script to read from your find command:

find . \( ! -name . -prune \) -type f -name "EXPORT_v1x0*" | awk -F'_' '$3<20120825' | while read fname
do
     > "$fname"
     rm "$fname"
done
5

How about this, I do need the date part as well here-

find . \( ! -name . -prune \) -type f -name "EXPORT_v1x0*" | awk -F'_' '$3<20120825' | while read fname
do
     > "$fname"
     rm "$fname"
done
6

Yes, I edited my post to include that as well. I hope this helps.

7 
rm: ./EXPORT_v1x0_20120811_11_T_065800_070000.dat.gz not removed: Disc quota exceeded

Still same exception I got. Any other thoughts.

8

What happened with truncation? Is size set to zero for this file?