Deleting the files based on the date's

Shell Programming and Scripting
1

I have to write one script which will delete the files in the below passion.

If today is 17-Feb-2010 then the script delete only 17-JAN-2010 files from the directory.

Could you please help me, How will I delete the files when the year is leap year, if today is 30th Mar 2010 then how will handle such scenarios.

I have written simple script for getting the yesterday's date but I do not understand how to develop this script.

bash-3.00$ cat calc_date_sample.sh

 v_todaysdate=`date +%d`
v_yesterday=$((`date +%e` -1))
v_month=`date +%m`
v_year=`date +%Y`

if [ $v_yesterday -eq "0" ]
then
  v_month=$((v_month-1))
    if [ $v_month -eq "0" ]
    then
       v_month=12
       v_year=$((v_year-1))
    fi
  set `cal $v_month $v_year`
  shift $(($# - 1))
  v_yesterday=$1
fi
echo "Previous Date : - " $v_yesterday-$v_month-$v_year
echo
echo "TodaysDate : - " $v_todaysdate-$v_month-$v_year

bash-3.00$
bash-3.00$

2

Is this date part of the filename, and in exactly the same format you listed? Or is this the file's date stamp that you are referring to here?