Hi,
I have a folder/dir which have file names as below.
file1.txt
file2.txt
file3.txt
.
.
Such files are added to the folder daily. I have to keep only latest 10 files in the folder and delete the old files.
I have tried several ways. But couldn't find a better logic.
ls -t|tail -n 10;ls|sort|uniq -u|xargs rm
or
rm `ls -t | awk 'NR>10'`
According to the standards, ls -t|tail -n 10 should give you the 10 newest files. And, ls -tr|tail -n 10 should give you the 10 oldest files.
However, on some systems, ls -t gives you multi-column output even when the output is not directed to a terminal. For, those systems, you also have to use the -1 (digit one; not letter ell) option to force single column output.
Try:
echo rm $(ls -t1 | awk 'NR > 10')
If that shows you the command you want to execute, remove the echo to actually run it.